The leaf material screw conveyor calculation _3787

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The leaf material screw conveyor calculation

To technical difficulties processing the helical blade is cutting. Figure 1 Structure of a screw conveyor. Motor 2. Reducer 3. Discharge port 4. Suspension bearings 5. Spiral blade 6, a feed opening of conventional cutting method leaves the conventional method, there are two cutting blades. One for cold forming method, and its basic process is: the raw materials strip by a pair of cold-rolling mill on the tapered roller compacted to form a continuous loop belt, and then guide them through the Spiral device, into a left (right) rotation, and have a certain pitch of the spiral blade. This method is more suitable for mass production,[link widoczny dla zalogowanych], mass production process for non-cutting, is more of a single blade by welding. The basic process is: first flat plate material into a single ring with a gap in the mold pressed into a single helical blade (a pitch), and then one by one by hand welded in the middle of a single blade shaft to form a continuous blade This method is simple, grain and feed business and more using this method. When the blade diameter D, pitch s, intermediate shaft diameter d is known, see Figure 2 below, cutting formula are: �� '0 one. . . . . . . . . . . . . . . . . . . . . . . . . . . ;. A ... .... . - A next wire! Fort Hall Leaf material calculated 45R = L = a = 2 ~ RL �� 360 ~ where: BU leaf width (HllT1), desirable b: Dd, I the length of an outer helix (coffee), L:, /, cream l - the length of the helix (a), l =, / r chew where all the symbols shown in Figure 2} 1. �� - _. I Figure 2 spiral blades and cutting blades size 2, with no gaps in the theory of computation in recent years, cutting the gap often is not removed,[link widoczny dla zalogowanych], only the ring can be cut (along A_A cut, as shown in Figure 3). This approach has the advantages are: save time and material, especially not in the same direction as the weld is not leaving a smooth motion. Incision but not removed after the ring welded to the shaft, around the axis rotation angle (0> 2) How much? It increased the distance along the axis (x> s) and how much? Quantitative because of this problem is not the solution resulting in cutting difficult. On this issue to be discussed below. Leaves space for the cylindrical shape of helical surface (cylindrical spiral surface is not developable surface, similar expansion can be started as shown in Figure 4), and numerous cylindrical spiral surface in turn, is composed of cylindrical helix. The equation for the circular helix: X = a �� c women ya'sinOCZ = KO (K Smile

Second, the differential �� on the type, was: dx = a a �� sin8 �� d. ay = a. eosO �� d. dZ = K �� dO Sichuan Animal Husbandry and Veterinary Research Institute No. l3 arc substituted into the differential equation dA =, / r do: dA:. de of the integrator: A: �� dOA:. 0A Figure 3, the sizes of materials not notched leaves spiral in Figure 4 approximate expansion for the cylindrical ring with a lack of El Blade, when 0 = 2, up a spiral pitch s,[link widoczny dla zalogowanych], then the arc length for the A:. 0 = �� a2 +() Sad

2) diameter of the blade and the shaft diameter d D into (2) was: external spiral arc: h = ~ / (7 (D) + S2 spiral arc: I = ~ / (7 (d) + S2 for the ring without the gap, the inside and outside the arc spiral were 2u'r and 2R, according to (1) they calculated the angle of rotation around the axis from the first base 0 eleven �� ()+() pennant for the notched circle is the distance along the axis of the rise in pitch. (3A) (3B) Sheng plastic one.,[link widoczny dla zalogowanych]! rotary cutting blade of the conveyor 47 without the band gap calculated ring increase the distance along the axis X = S + x (x increments),[link widoczny dla zalogowanych], the size is calculated as follows: one S-Xl will provide L'dL = R disc. b: 1: Substituting the above equation, after simplification can get: x : so D (4) a D c (+ d) q using equation (4) different models to calculate the screw conveyor, using notched leaves and leaves with no gaps in the rotation angle increased with the distance along the axis / c_ of differences. Table 1. Table 1 were calculated under the comparative feeding method 3 the calculation of two rings such as a blade diameter D: 400nlm, pitch S = 400mn.1, shaft diameter d = 70mlTl the screw conveyor, If its length is 20m, then: there are gaps in the number of blades = 20 = 20 = 50 (a) no gap in the number of blades = 20: Korea 20 = 41.5842 (a) shows that the screw conveyor vane ring without the gap with the economic potential is great.